On Tue, 24 Aug 2004, Parker Jones wrote: > Thanks for the helpful response, Tommi. It appears I have been violating > the assumptions for MM calculations. I'd like to calculate the energy of > the LHS and RHS of a reaction where substrates and products are small > metabolites. You mention that QM energies are comparable in some cases. LHS = left hand side, and RHS = right hand side of an equation, right? > In that case, can one simply sum the QM energies of the molecules of each > side? Any pointers to the assumptions of QM calculations would be much > appreciated. Yes, I think one can sum the QM energies of each side, and subtract them to get the (approximate?) delta-E for the reaction. Please note that 1) make sure the QM method used is "size-consistent" ; the energy for 2 separate non-interacting molecules should be 2x energy of a single molecule. Most methods are size-consistent, but it's good to check this. 2) the results describe the reaction in gas-phase conditions. In the real reaction some/all of the reactans/products can be liquids/solids but this is not taken in account, but the result is a gas-phase result. Solvation can favour reactans/products or both. Perhaps some programs/methods can approximate this as well. I can't give any references into this, but try looking for thermodynamic applications of QM methods. Regards, Tommi